Question

5. What is (a) the highest (b) lowest total resistance that can secured by
combination of four coils of resistance 4ohm, 8ohm, 12ohm and 24ohm​

Answer 1

Answer:

a) for highest resistance put all resistance in series = 4 + 8 + 12 + 24 = 48 ohm

b) for lowest resistance put all resistance in parallel 1/R = 1/4 + 1/8 + 1/12 + 1/24

1/R = ( 6 + 3 + 2 + 1 )/24

1/R = 12/24

1/R = 1/2

R= 2 ohm

Explanation:

hope u like solution