5. What is the percentage increase in linear momentum when the kinetic energy of an object increases by 21%?
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if velocity increased by 20%… KE = m(1.2v)^2/2.. So( P+0.20 P)*2 -P^2= 0. 44 P^2 ,the increase in KE. Therefore,0.44 P^2/P^2= 0.44 = 44%.
Explanation:
What is the percentage increase in the magnitude of linear momentum of the body? So the percentage increase, in the magnitude of linear momentum is 10%.
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