5. What is the perimeter of a sector of angle 45° of
a circle with radius 7 cm? (Use 7 = 22/7)
(CBSE 2008C)
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3
Answer:
19.5
Step-by-step explanation:
l=[45/360×2pi
5.5
p of sector OAB
=(7+7+5.5)
=19.5
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