Math, asked by abhishrma78523, 6 months ago

5. What is the sum of the digits of the decimal form
of the product 2^999 * 5^1001,
(a) 2
(b) 4​

Answers

Answered by AayushNigade
2

Step-by-step explanation:

Ans :7

=2^1999 * 5^2001

=2^1999 * 5^1999*5^2

=(2^1999 * 5^1999)*5^2

=10^1999*25

=25*10^1999

=2500000000000000000---------------0

=2+5+0+0+0--------------------------------+0

=7

Answered by manojsinghnld366
4

Answer:

7

Step-by-step explanation:

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