Question

5.

What will be the equilibrium constant at 127°C. If equilibrium constant at 27°C i 4 for reaction
N, + 3H, 2NH, AH = - 46.06 )
(1) 4 x 10
(2) 2 x 10
(3) 10
(4) 4 x 100​

Answer 1

Answer:

Correct option is

A

4×10 -2

N2

+3H2

⇌2NH 3

;ΔH=−46.06KJ

Given K at 27

0

C is 4

We know from Gibbs - Helomolt & equation

In( K2 K1)=−( RΔH )( T11 − T 2 1 )K 1 be at 127 0

equilibrium constant

K2 be at 27

0

C equilibrium constant

In( 4K 1 )=−( 8.314−46.06×10 3 )( 4001 3001 )

In( 4K 1 )=−4.61674K 1

=98.85×10 −4 K1

=395.41×10

−4

≈4×10 ^−2