Question

5. What will be the nature of roots of the quadratic equation 3√3 x^2 + 10x + √3 = 0?​

Answer 1

Answer:

Real and Equal

Step-by-step explanation:

To find nature of roots we need to find determinant.

$D={b^2-4ac}$

$=10^2-4*3\sqrt{3}*\sqrt{3}$

$=100-36$

$=64$

If determinant is a square the roots will be real and equal.

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