5. when 147 is divided by n the remainder is 4 when 255 is divided by n the remainder is 8 when 622 is divided by n the remainder is 11 find n?
Answers
here
nx = 147 - 4 = 143 (x is quotient)
ny = 255 - 8 = 247 (y is quotient)
nz = 622 - 11 = 611 (x is quotient)
find factor of 143, 247 and 611
We wil get 13 as common factor. So n is 13
Answer:
The required number n is 13.
Step-by-step explanation:
Consider the provided information.
When 147 is divided by n the remainder is 4. That means 147-4=143 is completely divisible by the number n.
When 255 is divided by n the remainder is 8. That means 255-8=247 is completely divisible by the number n.
When 622 is divided by n the remainder is 11. That means 622-11=611 is completely divisible by the number n.
Therefore, n is the HCF of the numbers 143, 247 and 611.
The prime factorization of the above number are:
143 = 13 x 11
247 = 13 x 19
611 = 13 x 47
The HCF is 13.
Hence, the number n is 13.