5. When a car is stopped by applying brakes, it stops
after travelling a distance of 100 m. If speed of car
is halved and same retarding acceleration is applied
then it stops after travelling a distance of
(1) 25 m
(2) 50 m
(3) 75 m
(4) 100 m
Answers
Answered by
42
Answer:
we use third equation of motion here. for first part, v.v-u.u=2a(100)...........(1) for second part, v.v -u.u/4=2as...........(2) from equation (1) and (2), s=25m
Answered by
2
Answer:
by using 3rd equation of motion , v^2 - u^2 = 2as
Explanation:
by substituting the value , s = 25 m
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