Question

5. When heated, potassium permangnate decomposes according to the following equation :
2KMnO4 →→ KMnO4 + MnO2 + O2
(i) Some potassium permangnate was heated in a test tube. After collecting one litre of oxygen at
room temperature, it was found that the test tube had undergone a loss in mass of
1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a
mass of 0.0825 g, calculate the relative molecular oxygen.
(ii) Given that the molecular mass of potassium permangnate is 158, what volume of oxygen
measured at room temperature, would be obtained by the complete decomposition of 15.8 g
of potassium permangnate ? (Molar volume of room temperature is 22.4 litres)​

Answer 1

Answer:

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Explanation: