Question

5-
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23.
Following information is given for the first order reaction of thermal decomposition of N.o, at
1
constant volume. N2O5(e) + N2048 +
N₂O 410 + Ž 0218
Sr No. Time (s) Total pressure (atm)
1.
0
0.50
2.
100
0.51​

Answer 1

Explanation:

Let the pressure of N2O5(g) decrease by 2xatm . As two moles of N2O5 decompose to give two moles of N2O5(g) and one mole of O2(g) , the pressure of N2O4(g) increase by 2xatm and that of O2(g) increases by xatm .

pt=pN2O5+pN2O4+pO2 

     =(0.5−2x)+2x+x=0.5+x 

x=pt−0.5 

pN2O5=0.5−2x=0.5−2(pt−0.5)=1.5−2pt 

      =(0.5−2x)+2x+x=0.5+x 

x=pt−0.5