Question

5/x-1+1/y-2=2;6/x-1 -3/y-2=1

Answer 1

Answer:

x = 4 and y = 5

Step-by-step explanation:

let 1/(x - 1) = a and 1/(y-2) = b

Now. 5a + b = 2 -eqn. 1

and 6a - 3b = 1. -eqn. 2

now multiply eqn. 1 by 3 and add eqn. 2 and eqn. 1,

now it will be, 15a + 3b = 6

6a - 3b = 1

now we will get 15a + 3b + 6a - 3b = 7

21a = 7

a = 1/3

now putting value of 'a' in eqn. 1,

5*(1/3) + b = 2

5/3 + b = 2

b = 2-(5/3)

b = (6-5)/3

thus, b = 1/3

putting values of a and b,

now, 1/(x-1) = 1/3

x-1 = 3

x = 3+1

=> x =4

and. 1/(y-2) = 1/3

y-2 = 3

y = 3+2

=> y = 5