5/x-1+1/y-2=2. 6/x-1-3/y-2=1 give me ans pl zz
Answers
Given pair of linear equation is
and
Let assume that
and
So, equation (1) and (2) can be rewritten as
and
can be further rewritten as
On adding equation (5) and (6), we get
On substituting the value of u in equation (5), we get
So, equation (3) and (4), can be rewritten as
Verification :-
Consider,
On substituting x = 4 and y = 5, we get
Hence, Verified
Consider,
On substituting the values of x and y, we get
Hence, Verified
Answer:
Solution
Given pair of linear equation is
1
5
=2 2 --- (1)
X
2
and
6
3
=1--- (2)
- 1 y-2
Let assume that
1
-(3)
=u-
1
and
1
-- (4)
y - 2
So, equation (1) and (2) can be rewritten as
5u+v = 2--- (5)
and
6u- 3v ==1
can be further rewritten as
3(2u - v) = 1
1
(6)
2u- v =
3
On adding equation (5) and (6), we get
1
7u=2+
3
6+1
Tu=
3
7u =
3
1
u= - (7)
3
On substituting the value of u in equation (5),
we get
5
+v= 2
3
5
2
3
V
6 -5
6-5
3
-- (8)
3
V =
So, equation (3) and (4), can be rewritten as
1
1
and
1
- 1
y-2
3
X
: x-1 =3 and y - 2 = 3
x= 3+1 and y = +2
X= 4 and
y 5
Verification
Consider,
5
1
- (1)
-1 Ty- 2.
X
On substituting x = 4 and y = 5, we get
5
1
= 2
5 2
4 1
5
1
3 2
5+ 2
3
2
3
2= 2
Hence,Verified
Consider,
6
3
X-1y-21-- (2)
On substituting.the values of x andy, we get
6
3
1
41 5-2
6
3
= 1
3
3
21=1
1=1
Step-by-step explanation:
hope it's helpful