Question

5(x-1)+2(x+3)+6=0 how to check this equation​

Answer 1

Step-by-step explanation:

5(x-1)+2(x+3)+6=0

5x-5+2x+6+6=0

5x+2x-5+6+6=0

7x+7=0

7x=-7

divide 7 on both side

x=-1

now check by putting the value of x in question

5(-1-1)+2(-1+3)+6=0

5(-2)+2(2)+6=0

-10+4+6=0

-10+10=0

0=0