5/x+1-2/y-1=1/2,10/x+1+2/y-1=5/2
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This is the solution..
Hope it helps!
Hope it helps!
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rounak07:
thanks
Answered by
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Let 1/x be u and 1/y be v
therefore,
5u-2v=1/2...........eqn(i)
10u+2v=5/2.......eqn(ii)
on solving (i) and (ii)
-2v and +2v gets canceled
hence,
15u=3
u=3/15
u=1/5
u=1/5
1/x=1/5
therefore x=5
substituting x=5 in 5/x+1-2/y-1=1/2
5/5-2y=1/2
1-2y=1/2
taking LCM
y-2/y=1/2
cross multiplying
2y-2=y
2y-y=2
y=2
hence x=5 and y=2
therefore,
5u-2v=1/2...........eqn(i)
10u+2v=5/2.......eqn(ii)
on solving (i) and (ii)
-2v and +2v gets canceled
hence,
15u=3
u=3/15
u=1/5
u=1/5
1/x=1/5
therefore x=5
substituting x=5 in 5/x+1-2/y-1=1/2
5/5-2y=1/2
1-2y=1/2
taking LCM
y-2/y=1/2
cross multiplying
2y-2=y
2y-y=2
y=2
hence x=5 and y=2
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