5/x+1 - 2/y-1 = 1/2
10/x+1 - 2/y-1 = 5/2
reduce them to pair of linear equations!!
Answers
Given equations are-
5/x+1 - 2/y-1 = 1/2 ---eq(1)
And,
10/x-1 - 2/y-1 = 5/2----eq(2)
Let 1/x+1 = p and 1/y-1 = q
By Putting the values of x and y in eq(1) and eq(2) we get--
5p - 2q = 1/2
Or, 10p - 4q = 1 ---eq(3)
{transporting 2 towards LHS}
10p - 2q = 5/2
Or, 20p - 4q = 5-----eq(4)
{transporting 2 towards LHS}
Therefore the given equations are now reduced to pair of linear equation {eq(3) and eq(4)} now we can solve it easily.
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Answer:
Let 1/x+1 = m
1/y-1 = n
Equations:
5m - 2n = 1/2
10m - 2n = 5/2
Solution:
=> 5m - 2n = 1/2
=> 10m - 4n = 1
=> m = (1 + 4n)/10
10m - 2n = 5/2
=> 20m - 4n = 5
Put value of m:
=> 2 + 8n - 4n = 5
=> 4n = 3
=> n = 3/4
m = (1 + 4n)/10 = (1 + 3)/10
=> m = 4/10 = 2/5
m = 1/x+1 = 2/5
=> 5 = 2x + 2
=> 2x = 3
=> x = 3/2
n = 1/y-1 = 3/4
=> 4 = 3y - 3
=> 7 = 3y