Question

5/x+1-2/y-1=1/2 and 10/x+1+2/y-1=5/2 find x andy

Answer 1

Answer:

x=4,y=(11/3)

Step-by-step explanation:

given 5/(x+1)-2/(y-1)=(1/2)

10/(x+1)+2/(y-1)=(5/2)

let k=x+1; m=y-1

then (5/k)-(2/m)=(1/2).....(1)

(10/k)+(2/m)=(5/2)....(2)

adding (1)st equation and (2)nd equation

we get,

(15/k)=(6/2)

(15/k)=3

(15/3)=k

5=k

i.e. x+1=5

x=5-1

x=4

we get k=5, then substitute the 'k' value in (1)st equation or (2)nd equation

here I am substituting the 'k' value in equation (1)

(5/4)-(2/m)=(1/2)

(5/4)-(1/2)=(2/m)

(5/4)-(2/4)=(2/m)

(3/4)=(2/m)

m=[2(4)]/3

m=8/3

i.e. y-1=(8/3)

y=(8/3)+1

y=(8/3)+(3/3)

y=11/3

therefore x and y values are 4,(11/3)

Answer 2

Answer:

x=4,y=(11/3)

Step-by-step explanation:

given 5/(x+1)-2/(y-1)=(1/2)

10/(x+1)+2/(y-1)=(5/2)

let k=x+1; m=y-1

then (5/k)-(2/m)=(1/2).....(1)

(10/k)+(2/m)=(5/2)....(2)

adding (1)st equation and (2)nd equation

we get,

(15/k)=(6/2)

(15/k)=3

(15/3)=k

5=k

i.e. x+1=5

x=5-1

x=4

we get k=5, then substitute the 'k' value in (1)st equation or (2)nd equation

here I am substituting the 'k' value in equation (1)

(5/4)-(2/m)=(1/2)

(5/4)-(1/2)=(2/m)

(5/4)-(2/4)=(2/m)

(3/4)=(2/m)

m=[2(4)]/3

m=8/3

i.e. y-1=(8/3)

y=(8/3)+1

y=(8/3)+(3/3)

y=11/3

therefore x and y values are 4,(11/3)