Question

5^x+ 12^x= 12^x then velue of x=?

Answer 1

5 ^x+12^x=12^x
5^x=0
xlog5=log 0
xlog5= log 0
x= log0/log5

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Answer 2

5^x+12^x=12^x
5^x+(2×2×3)^x=(2×2×3)^x
5^x+(2^2×3)^x=(2^2×3)^x
5^x+2^2x×3^x=2^2x×3^x
comparing powers..
x+2x×x=2x×x
x=0