Math, asked by u2005, 1 year ago

5(x-13) = 10x -(2x+5)

Answers

Answered by Anonymous
3

Simplifying

5[x + -13] = 10x + -1[2x + 5]


Reorder the terms:

5[-13 + x] = 10x + -1[2x + 5]

[-13 * 5 + x * 5] = 10x + -1[2x + 5]

[-65 + 5x] = 10x + -1[2x + 5]


Reorder the terms:

-65 + 5x = 10x + -1[5 + 2x]

-65 + 5x = 10x + [5 * -1 + 2x * -1]

-65 + 5x = 10x + [-5 + -2x]


Reorder the terms:

-65 + 5x = -5 + 10x + -2x


Combine like terms: 10x + -2x = 8x

-65 + 5x = -5 + 8x


Solving

-65 + 5x = -5 + 8x


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '-8x' to each side of the equation.

-65 + 5x + -8x = -5 + 8x + -8x


Combine like terms: 5x + -8x = -3x

-65 + -3x = -5 + 8x + -8x


Combine like terms: 8x + -8x = 0

-65 + -3x = -5 + 0

-65 + -3x = -5


Add '65' to each side of the equation.

-65 + 65 + -3x = -5 + 65


Combine like terms: -65 + 65 = 0

0 + -3x = -5 + 65

-3x = -5 + 65


Combine like terms: -5 + 65 = 60

-3x = 60


Divide each side by '-3'.

x = -20


Simplifying

x = -20


Answered by Anonymous
3

AHOY USER !!!


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HERE IS UR ANSWER --


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SIMPLIFY ::


 5(x-13) = 10x - (2x + 5)


Multiply 5 with x and with (-3) in the LHS and open the bracket in the RHS.


  5x - 65 = 10x - 2x - 5


Now subtract 2x from 10x in the RHS..


 5x - 65 = 8x - 5


Now take 8x in the LHS by changing the sign to ( - ) and take (-65) to RHS by changing the sign to ( + )..


 5x - 8x = -5 + 65


Now subtract 8x from 5x in the LHS and then subtract 5 from RHS..


 -3x = 60


Now in the LHS , 3 is in multiply , so take it in the RHS in the form of division.


 x = 60/(-3)


 x = 20/(-1)


 x = -20


HOPE IT HELPS !!!!



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