Math, asked by muggie136ab2013, 9 months ago

5/x-2 + 1/x-1 = 6/x, where x ≠ 0,1,2​

Answers

Answered by aadya74
1

Answer:

x=-18/11

Step-by-step explanation:

5/x-2+1/x-1=6/x

5x-5+x-2/(x-2)(x-1)=6/x

6x-7/x^2-x-2x+2=6/x

6x-7/x^2-3x+3=6/x

x(6x-7)=6(x^2-3x+3)

6x^2-7x=6x^2-18x+18

6x^2-6x^2-7x+18x+18=0

-7x+18x+18=0

11x+18=0

11x=-18

x=-18/11

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