Question

5(x - 2) - 2 (x + 1) = 3​

Answer 1

Answer:

x = 5

hope it helpssss.....

Answer 2

The value of x is 4 or -2.09

Solution:

Given that solve for "x"

\frac{2}{x+1}+\frac{3}{2(x-2)}=\frac{23}{5x}x+12+2(x−2)3=5x23

On cross multiplication we get,

\frac{2 \times 2 \times(x-2)+3 \times(x+1)}{(x+1) \times 2 \times(x-2)}=\frac{23}{5x}(x+1)×2×(x−2)2×2×(x−2)+3×(x+1)=5x23

On simplification we get,

\frac{4 \times(x-2)+3 \times(x+1)}{(x+1) \times 2 \times(x-2)}=\frac{23}{5 x}(x+1)×2×(x−2)4×(x−2)+3×(x+1)=5x23

\begin{gathered}\begin{array}{c}{\frac{4 x-8+3 x+3}{(x+1) \times 2 \times(x-2)}=\frac{23}{5 x}} \\\\ {\frac{7 x-5}{(x+1) \times 2 \times(x-2)}=\frac{23}{5 x}}\end{array}\end{gathered}(x+1)×2×(x−2)4x−8+3x+3=5x23(x+1)×2×(x−2)7x−5=5x23

Again on cross multiplication we get,

\begin{gathered}\begin{array}{l}{(7 x-5) \times(5 x)=23 \times 2 \times(x+1) \times(x-2)} \\\\ {35 x^{2}-25 x=46 x\left(x^{2}-1 x-2\right)} \\\\ {35 x^{2}-25 x=46 x^{2}-46 x-92} \\\\ {46 x-25 x=46 x^{2}-35 x^{2}-92} \\\\ {21 x=11 x^{2}-92} \\\\ {11 x^{2}-21 x-92=0}\end{array}\end{gathered}(7x−5)×(5x)=23×2×(x+1)×(x−2)35x2−25x=46x(x2−1x−2)35x2−25x=46x2−46x−9246x−25x=46x2−35x2−9221x=11x2−9211x2−21x−92=0

Let us use quadratic formula to solve for "x"

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}x=2a−b±b2−4ac

Here a = 11 and b = -21 and c = -92

\begin{gathered}x= \frac{21 \pm \sqrt{441+4048}}{2 \times 11} \\\\ x=\frac{21 \pm \sqrt{4489}}{22} \end{aligned}\end{gathered}

x=\frac{21 \pm 67}{22}x=2221±67

\begin{gathered}\begin{array}{l}{\text { Now, } x=\frac{21+67}{22}=4} \\\\ {\text {Or}} \\\\ {x=\frac{21-67}{22}=-2.09}\end{array}\end{gathered} Now, x=2221+67=4Orx=2221−67=−2.09

Hence, the value of x is 4 or -2.09

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