Question

√5 x^2 + 8x - 4√5

How to get roots of it without sridharacharya method​

Answer 1

Step-by-step explanation:

compare eqn with ax^2+bx+c =0

a=√5, b=8 c= - 4√5

b^2-4ac = 8^2 - 4*√5*(-4√5)

= 64 + 80

= 144

using formula

$x = - b + - \sqrt{ {b}^{2} } - 4ac \div 2a$

_______

X = -b + -√b^2 -4ac

2a

X =-8+- √144

2* √5

x = 8+12. or. x = 8 -12

2√5. 2√5

X= 20.

2√5