5(x+3)=3y 2x_y=0
pls... answer by elimination method.
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Solution:-
Given Equations :-
Equation I,
=) 5( x + 3) = 3y
=) 5x + 15 = 3y
=) 5x - 3y + 15 = 0
=) 5x - 3y = -15
Equation II,
=) 2x - y = 0
Multiplying eq (2) by 3. we get,
=) 6x - 3y = 0
Now,
5x - 3y = -15
6x - 3y = 0
_____________
- x = - 15
=) x = 15
Now,
Substituting [ x = 15 ] in eq (2). we get,
=) 2x - y = 0
=) 30 - y = 0
=) y = 30.
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