Question

{5(x-3) / 6} -x = 1- x/9
solve and verify

Answer 1

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The fraction is...

$\frac{5(x - 3)}{6} - x = 1 - \frac{x}{9}$

Solve the bracket...

$\frac{5x - 15}{6} - x = 1 - \frac{x}{9}$

Take the LCM of denominators...

$\frac{5x - 15 - 6x}{6} = \frac{9 - x}{9}$

Reduce the denominators to simplest forms and solve the required in numerator...

$\frac{ - x - 15}{2} = \frac{9 - x}{3}$

By Cross Multiplication...

$3( - x - 15) = 2(9 - x)$

$- 3x - 45 = 18 - 2x$

$- 3x + 2x = 18 + 45$

$- x = 63$

The answer is...

$x = - 63$

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Answer 2

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The fraction is...

\frac{5(x - 3)}{6} - x = 1 - \frac{x}{9}

6

5(x−3)

−x=1−

9

x

Solve the bracket...

\frac{5x - 15}{6} - x = 1 - \frac{x}{9}

6

5x−15

−x=1−

9

x

Take the LCM of denominators...

\frac{5x - 15 - 6x}{6} = \frac{9 - x}{9}

6

5x−15−6x

=

9

9−x

Reduce the denominators to simplest forms and solve the required in numerator...

\frac{ - x - 15}{2} = \frac{9 - x}{3}

2

−x−15

=

3

9−x

By Cross Multiplication...

3( - x - 15) = 2(9 - x)3(−x−15)=2(9−x)

- 3x - 45 = 18 - 2x−3x−45=18−2x

- 3x + 2x = 18 + 45−3x+2x=18+45

- x = 63−x=63

The answer is...

x = - 63x=−63

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