Question

5/x-3/y=1 and 3/2x+2/2y=5 by substitution method ​

Answer 1

Answer:

3x+2y=1 ------- (1)

2x−3y=5 ------ (2)

From equation 1:

2y=13x

2y=1−3x

Y=

2

1−3x

​

Substitute the value of y in equation 2:

2x−3y=5

2x3(

2

1−3x

​

)=5

4x3+9x=10

13x=10+3

X=

13

13

​

=1

Now, Substitute x=1 in equation 1 :

3x+2y=1

3x1+2y=1

2y=13

Y=

2

−2

​

Y=−1

Therefore the solution is:

Answer 2

Answer:

Let 1/x= a and 1/y=b

Now equation will be:-

1. 5a-3b=1
2. 3a+2b=10

From equation first:-

• a=(1+3b)/5

Now put the valve of a in eq first

so,

3(1+3b)/5+2b=10

3+9b+10b=50

19b=47

b=47/19

Now from eq first

a= [1+3(47/19)]/5

a=160/95=32/19

So, x = 1/a =19/32

y=1/b=19/47

Hence the value of x and y will be19/32 and 19/47 respectively

Hope its help uh❤