Question

5+x/5-x-5-x/5+x=15/4 find x

Answer 1

( 5 +x ) /( 5 - x ) - ( 5 + x ) / ( 5 + x ) = 15 / 4

( 5 + x )^2 -( 5 - x )( 5 + x ) / (5)^2 - (x)^2 =15 / 4

25 + x^2 + 10x - 25 + x^2 / 25 - x^2
= 15 / 4

2x^2 + 10 x / 25 - x^2 =
15 / 4

8x^2 + 40x = 375 - 15 x^2

=23x^2 + 40x - 375= 0

x( 23x + 40 ) - 375 = 0

min.value of "x"

23x + 40 = 0

23x = - 40

x = - 40 / 23

●hope it helps ●

Answer 2

-25/3 is the value of x.

Step-by-step explanation:

$\frac{5 + x}{5 - x } - \frac{5 - x}{5 + x} = \frac{15}{4}$

$\frac{(5 + x)^2 - (5-x)^2}{(5-x) (5+x)} = \frac{15}{4}$

⇒ $\frac{25 + x^2 + 10x - (25 + x^2 - 10x)}{25 - x^2} = \frac{15}{4}$

⇒ $\frac{ 25 + x^2 + 10x - 25 - x^2 + 10x}{25 - x^2} = \frac{15}{4}$

⇒ $\frac{20x}{25 - x^2} = \frac{15}{4}$

⇒ 80x = 375 - 15x^2

⇒ 15x^2 + 80x - 375 = 0

⇒ 3x^2 + 16x - 75 = 0

x = (-b ± $\sqrt{b^2 - 4ac}$)/2a

= (-16 ± $\sqrt{256 + 900}$)/6

= (-16  ± 34)/6 = 18/6 = 3

= (-16-34)/6 = -50/6 = -25/3

$x = \frac{-25}{3}$

Learn more: Find the value of X

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