Question

√5-x=5-x2 find the value of x​

Answer 1

Answer:

$\sqrt{5} - x = 5 - {x}^{2} \\ {x}^{2} - 5 + \sqrt{5} - x = 0 \\ x(x - 1) - \sqrt{5} + \sqrt{5} + \sqrt{5} = 0 \\ x(x - 1) - \sqrt{5} + 2 \sqrt{5} = 0 \\ x(x - 1) - \sqrt{5} (1 - 2) = 0 \\ x(x - 1) + \sqrt{5} = 0$