Math, asked by kanchantripathi377, 11 months ago

5/x + 6y = 13 ;3/x + 4y = 7 please solve this ​

Answers

Answered by dineshkumaryadav55
3

Answer:

x = 1/5

y = -2

Step-by-step explanation:

let 1/x = a

5a+6y=13. ...(i)

3a+4y = 7. ... (ii)

we see that LCM of 5 and 3 is 15

for making 5a to 15a, multiply by 3 in (i)

for making 3a to 15a, multiply by 5 in (ii)

(5a+6y=13)*3. ... (iii)

(3a +4y=7)*5. ...(iv)

15a+18y=39. ...(iii)

15a+20y=35. ....(iv)

Subtract (iii) from (iv)

15a+20y=35 - (15a+18y=39)

15a+20y=35 - 15a-18y-39

2y= -4

y= -2

putting value of y in (ii)

3a +4y=7

3a -8 =7

3a = 15

a = 5

we have assumed a = 1/x

1/x = 5

x=1/5

Answered by brainlyshacker58
1

\red{Hola \ !!!}

Answer:

x = 1/5

y = -2

Step-by-step explanation:

let 1/x = a

5a+6y=13. ...(i)

3a+4y = 7. ... (ii)

we see that LCM of 5 and 3 is 15

for making 5a to 15a, multiply by 3 in (i)

for making 3a to 15a, multiply by 5 in (ii)

(5a+6y=13)*3. ... (iii)

(3a +4y=7)*5. ...(iv)

15a+18y=39. ...(iii)

15a+20y=35. ....(iv)

Subtract (iii) from (iv)

15a+20y=35 - (15a+18y=39)

15a+20y=35 - 15a-18y-39

2y= -4

y= -2

putting value of y in (ii)

3a +4y=7

3a -8 =7

3a = 15

a = 5

we have assumed a = 1/x

1/x = 5

x=1/5

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