Math, asked by ys267449, 7 months ago

5{x/x+1}^2 - 4{x/x+1}-1=0 where x not=-1 solve by factorization method

Answers

Answered by Anonymous
2

Let x/x+1 = k

5k^2 - 4k - 1 = 0

=> 5k^2 - 5k + k - 1 = 0

=> 5k(k - 1) + 1(k - 1) = 0

=> (5k + 1)(k - 1) = 0

=> k = 1, -1/5

When k = -1/5:

x/x+1 = -1/5

5x = -x - 1

6x = -1

x = -1/6

When k = 1:

x/x+1 = 1

x = x + 1

Squaring on both sides:

x^2 = x^2 + 1 + 2x

2x + 1 = 0

x = -1/2

Answered by Anonymous
0

Answer:

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Lyricist: Claude Joseph Rouget de Lisle

First performance: May 1792

Place composed: Strasburg, Michigan, United States

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