5 / (x+y) + 2 / (x-y) = 6 and 32 / (x+y) + 1 / (x-y) = 65/2 find x ad y
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put x+y = 1 and x-y = 2 in both equation.. so that they satisfy the condition so that,
=> x+y = 1
=> x-y = 2 => x = 2+y
=> 2+y+y = 1
=> 2+2y = 1
=> y = -1/2
=> x = 2-1/2 = 3/2
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