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5. x² – (√2+1) x + √2=0
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will be in brackets
Step-by-step explanation:
we will take common
(x^2_x )+(-√2x+√2)
now we will take common
X(x_1)_√2(x-1)
we will make pairs
(x_√2)(x_1)=0
sorry I thought it to be x^2_(√2+1)X+√2
this much question
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