Question

5 x²-6x+1 where x=1​

Answer 1

P(x) = 5 x²-6x+1

Putting x = 1

P(1) = 5 (1)² - 6× 1 + 1

P(1) = 5×1 -6×1 +1

P(1) = 5 -6 +1

P(1) = 6 -6

P(1) = 0

Hope this is helpful ..... : )