Question

5.x²+x+1 = 0 solve by factorization​

Answer 1

Answer:

${x}^{2} + x + 1 = 0 \\ \implies \: a {x}^{2} + bx + c = 0 \\ a = 1 \\ b = 1 \\ c = 1 \\ {b}^{2} - 4ac = {1}^{2} - 4 \times 1 \times 1 \\ = 1 - 4 = - 3 < 0 \\ \because \: discriminant \: of \: the \: given \: \\ quadratic \: equation \: is \: not \: real. \\ \therefore \: its \: solution \: is \: not \: possible.$