Question

5(y-1)-3(y-2)+2(y+3)=0

Answer 1

$\sf\underline{ Heya \: Math's \:lover}\dag$

$→5(y-1)-3(y-2)+2(y+3)=0$

$→5(y-1)-3(y-2)+2(y+3)=0 \\\\→5y-5-3y-6+2y+6=0\\\\→5y+2y-3y-5-6+6=0\\\\→4y-5 =0\\\\→4y = 5\\\\→y = 5/4$

More information :-

• → Here y is a variable.

• →Variable is a number which we have to find out.

Hope it helps you dear