Question

5- y for y = 2.
plss give soon​

Answer 1

Step-by-step explanation:

$\frac{y - 2}{y - 5} = \frac{y + 3}{y + 5} \\ \\ (y - 2)(y + 5) = (y + 3)(y - 5) \\ \\ {y}^{2} + 5y - 2y - 10 = {y}^{2} - 5y + 3y - 15 \\ \\ 3y - 10 = - 2y - 15 \\ \\ 3y + 2y = 10 - 15 \\ \\ 5y = - 5 \\ \\ y = - 1$

Answer 2

$\tt \sf \huge \underline\: \underline \red{Δƞƨωεя}$

$\tt \large{ \frac{y - 2}{y - 5} = \frac{y + 3}{y + 5} }$

$\tt \underline{(y - 2)(y + 5) = (y + 3)(y - 5)}$

$\tt \underline{ {y}^{2} + 5y - 2y - 10 = {y}^{2} - 5y + 3y - 15}$

$\tt \underline{3y - 10 = - 2y - 15}$

$\tt \underline{3y + 2y = 10 - 5}$

$\tt \underline{5y = - 5}$

$\tt \large\underline{y = - 5}$