Question

5 year ago the age of fathet is 7 time more than than his son. 5year hence the age of father is 3 time more than his son than fins present age​

Answer 1

Answer:

Step-by-step explanation:

Let his father's age be x and son's age be y.

Five years ago:

x-5=7(y-5)

x-5=7y-35

x-7y+30=0......eq1

Five years hence:

x+5=3(y+5)

x+5=3y+15

x-3y-10=0........eq2

By using elimination method, from 1 and 2, we get,

x-3y-10=0

x-7y+30=0

(-)(+)(-)

4y-40=0

y=40/4

y=10..........eq3

x-7(10)+30=0 (substitute y=10 from eq3)

x-70+30=0

x-40=0

x=40

Father's age=40 and son's age=10