Question

5 year hence father's age will be three times the age of his son 5 year ago father was 7 times as old as his
son find their ages of father and son

Answer 1

Answer:

x=40yrs y=10yrs

Step-by-step explanation:

let current age of

father-x

son-y

after 5 yrs: x+5=3(y+5)

before 5yrs : x-5=7(y-5)

solving both the equations we get

y=10yrs and x=40

Answer 2

Answer:

Step-by-step explanation:

Let the present age of the father =x yrs

&the present age of son =y yrs

ATQ, x+5=3(y+5)

=>x+5=3y+15

=>x-3y=10 —-———eq-1.

&x-5=7(y-5)

=>x-5=7y-35

=>x-7y=-30————eq-2

(elimination method)

By multiplying 1 to eq-1 &1 to eq-2 and Subtracting them.

x - 3y = 10

x - 7y = - 30

(-) (+) (+)

=>4y=40

=>y=10

Now, by putting the value of y in eq-1

x-3×10=10

=>x-30=10

=>x=40

Therefore, present age of father is 40yrs & present age of son is 10yrs(ans).

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