Question

5 year hence the age of father shall bw 3 times the age of son while 5 years earlier the age of father was 7 times the age of the son then find their present ages?​

Answer 1

$\bf\large\underline\green{Solution :-}$

➤ Let father's age = x

son's age = y

Five years hence, age of father = x+5 

                                 age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

Five years ago, age of father = x-5 

                                 age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10  <<<<<<<<son's age

   x = 3y +10 = 40 <<<<<<father's age

❒________________________

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