Question

5 years A mother was 7 times as old as her daughter five years hence she will be 3 times as old as her daughter find this present age.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$let \: the \: age \: of \: daughter \: 5 \: years \\ ago = x \\ age \: of \: mother \: 5 \: years \: ago = 7x \\ \\ present \: age \: of \: daughter =(x + 5) \: years \\ present \: age \: of \: mother = (7x + 5)years \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: acc. \: to \: ques - \\ \\ = > 3(x + 10) = (7x + 10) \\ = > 3x + 30 = 7x + 10 \\ = > 30 - 10 = 7x - 3x \\ = > 20 = 4x \\ = > x = \frac{20}{4} \\ = > x = 5 \\ \\ present \: age \: of \: daughter =(5 + 5) = 10 \: years \\ present \: age \: of \: mother = (7 \times 5 + 5) \\ = 40years$
MARK IT AS BRAINLIST.