Question

5 years ago a father’s age was 5 times that of his son. After 3 years , the father’s age would be 3 times that of his son. Find their present ages.

Answer 1

Answer:

Present age of son is 10 years and that of father is 30 years

Step-by-step explanation:

The age of the father 5 yr ago was 5 times the age of his son. At present the father's age is 3 times that of his son. What is the present age of the father?

Let the present age of son be x

And that of father be y

According to the question

3x=y ----(1)

Also

5 years ago

y-5=5(x-5) ----(2)

Substitute the value of y from (1) in (2)

3x-5=5x-25

25-5=5x-3x

2x=20

x=10

y=3x

y=30

Present age of son is 10 years and that of father is 30 years

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Answer 2

Answer:

FATHER'S age is 40

Son's age is 10

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Step-by-step explanation:

Father's age =40 years, Son's age =10 years

Let the father present age =x years and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10....eq1

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

Hence, Father present age =40 years

Son present age =10 years