Question

5 years ago a man's was 5 times the age of his daughter's 3 years hence twice his age will be equal to 6 times his daughter's age .what are their present ages?​

Answer 1

Answer:

let the daughter age be x

after 5years manvs age will be x+5

3year hence his age will be x+6

B/Q

(x+5)(x+6)

x²+6x+5x+30

x²+11x+30

there fore his present age will be x²+11x+30