Math, asked by Priyu11, 1 year ago

5 years ago A man was 7 times as old as his son 5 years hence the father will be 3 times as old as his son find their present ages

Answers

Answered by Bhunesh11
2
Let the past age of son = x
Let the past age of father = 7x
So,
Present ages are x+5 and 7x+5
Future age of son = x+10
Future age of father = 7x+10
Given
7x+10 = 3*(x+10)
7x+10 = 3x+30
7x-3x = 30-10
4x = 20
x = 20/4
x = 5
7x = 35
x+5 = 10
7x+5 = 40
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