5 years ago A man was 7 times as old as his son 5 years hence the father will be 3 times as old as his son find their present ages
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Let the present ages of father nd son be X&Y respectively
(x-5)=7(y-5)
x-5=7y-35
x=7y-30...............(1)
(x+5)=3(y+5).............substitue the value of ................equation (1) in this equation
(7y-30+5)=3y+15
4y-25=15
4y=40
y=10
x=7y-30
x=40
There ages of father nd son are 40&10 respectively
(x-5)=7(y-5)
x-5=7y-35
x=7y-30...............(1)
(x+5)=3(y+5).............substitue the value of ................equation (1) in this equation
(7y-30+5)=3y+15
4y-25=15
4y=40
y=10
x=7y-30
x=40
There ages of father nd son are 40&10 respectively
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