Question

5 years ago a man was 7 times as old as his son . five years after he is 3 time old his son find the son and fathers present age

Answer 1

let the age of man be x
let age of his father be y

5 years ago,
his age=x-5
his son's age=y-5
ATQ
x-5=7(y-5)
x-5=7y-35
x=7y-30-(1)

now,5 years hence,
his age=x+5
his son's age=y+5

ATQ
x+5=3(y+5)
x+5=3y+15
(7y-30)+5=3y+15(from (1))
7y-25=3y+15
7y-3y=25+15
4y=40
y=10

now put x in (1)
x=(7×10)-30
x=70-30
x=40

so,man's age=40
his son's age=10