Question

5 years ago a man was 7 times old as his son .5 years hence, the father will be 3 times as old as his son . find their present age

Answer 1

Answer:

Man = 40, Son = 10

Step-by-step explanation:

Define x:

Let x be the age of the son 5 years ago

The man = 7x

Find their present age now:

Son = x + 5

Man = 7x + 5

Find their age 5 years later:

Son = x + 5 + 5 = x + 10

Man = 7x + 5 + 5 = 7x + 10

Solve x:

The Man is 3 times as old as his son

7x + 10 = 3(x + 10)

7x + 10 = 3x + 30

4x = 20

x = 5

Find their present age:

Son = x + 5 = 5 + 5 = 10 years old

Man = 7x + 5 = 7(5) + 5 = 40 years old

Answer: The man is 40 and the son is 10 years old.

Answer 2

Answer:

Father's present age is 40

Son's present age is 10

Step-by-step explanation:

In the attachments I have answered this problem.

See the attachment for detailed solution.

I hope this answer helps you