Question

5 years ago a man was seven times as old as his son. Five years hence ,the father will be three times as old as his son. Find the present ages .

Answer 1

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years.

Present age of son =(x+5)years

Present age of father =(7x+5)years

5 years later their age will (x+10) and (7x+10)years

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years