Question

5 years ago A was 5 times as old as B. 3 years hence A will be 3 times as old as B. Find their present ages.​

Answer 1

Step-by-step explanation:

let present age of A be x

let present age of B be y

5 years ago

age of A = x-5

age of B = y-5

x-5=5(y-5) (1)

3 years hence

age of A=x+3

age of B=y+3

x+3=3(y+3) (2)

from 1 and 2

x-5=5y-25

x-5y+20=0

x+3=3y+9

x-3y-6=0

solving the above equation

x-5y+20=0

x-3y-6=0

x=45. y=13

present age of A=45

present age of B=13