5 years ago, A was thrice as old as B and 10 years later. A shall be twice as old as B . what are the present ages of A and B?
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Heya!
Let the age of A be x years and B be y years.
Then, ATQ,
Five years ago :
x - 5 = 3 (y-5)
x - 5 = 3y - 15
x - 3y = -10 (i)
Ten years later :
x + 10 = 2 (y + 10)
x + 10 = 2y + 20
x - 2y = 10 (ii)
Subtracting both the equations,
x-3y = -10
x-2y = 10
which is, y = 20
Now finding x,
x - 2y = 10
x - 40 = 10
x = 10 + 40 = 50
Therefore, A's age is 50 years while B's age is 20 years
Hope it helps!
Let the age of A be x years and B be y years.
Then, ATQ,
Five years ago :
x - 5 = 3 (y-5)
x - 5 = 3y - 15
x - 3y = -10 (i)
Ten years later :
x + 10 = 2 (y + 10)
x + 10 = 2y + 20
x - 2y = 10 (ii)
Subtracting both the equations,
x-3y = -10
x-2y = 10
which is, y = 20
Now finding x,
x - 2y = 10
x - 40 = 10
x = 10 + 40 = 50
Therefore, A's age is 50 years while B's age is 20 years
Hope it helps!
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