Question

5 years ago, A was thrice as old as B and 10 yrs later, A shall be twice as old as B. What are the present ages of A and B.

Answer 1

let the present ages of a and b be x and y respectively
a/q
5 years ago
3(x-5)=(y-3). _2
now after 10 yes.
2(x+10)=(y+10). _1
now solve the equn 1 and 2

Answer 2

let A and B any person
5 years ago
according to the question
3(a-5) =(b-5)
again 10 year after
2(a+10) =(b+10)
solving the problems
3a-15=b-5
3a-b=5+15
3a-b=20
a=20+b/3 ..........(1)
2a+20=b+10
2a-b=10-20
2a-b= -10
putting value of a
20+b/3-b=-10
20+b-3b/3=-10
20-2b/3=-10
20-2b=-30
-2b= -30-20
-2b=-50
b= -50/-2
b=25
putting value of b in equation 1
a=20+25/3
a=45/3
a=15
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