Question

5 years ago age of father was 3.5 times of the age of son.7 years hence age of father will become 2.5 times age of son

Answer 1

Solution: Let the present age of father be 'X' year.
and the present age of his son be 'y' year.
A/Q,
5 years ago age of father was 3.5 times of the age of son.
So (X -5)=3.5(y-5)
=>x-5=3.5y-17.5
=>x-5+17.5-3.5y=0
=>x-3.5y+12.5=0...........(1)

Again,
7 years hence age of father will become 2.5 times age of son.
So, (x+7)=2.5(y+7)
=>(x+7)=2.5y+17.5
=>x+7-17.5-2.5y=0
=>x-2.5y-10.5=0...............(2)
Now, From (1),we have
x=3.5y-12.5 ...............(3)
Substituting the value of 'X' in equation (2),we have
3.5y-12.5-2.5y-10.5=0
=>y=23
Substituting the value of 'y' in equation (3),we have
X= 3.5 X 23 - 12.5
X =80.5 -12.5
x=68

Answer 2

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