Question

5 years ago age of one sister was twice the age of other sister .5 years hence their ages will be in the ratio 2:3.find their present age.

Answer 1

I consider hence as after because it's unfit there.

5 years ago ratio of two sisters' ages =1:2
Let's consider them 1x and 2x
After 5 Years from now (ten's years from then)
their ages wil be x+10 , 2x+10

That ratio is given as 2:3
Therefore,
x+10 : 2x+10 = 2:3
= x+10 / 2x+10 = 2/3
= (x+10) * 3 = 2 * (2x+10)
= 3x + 30 = 4x + 20
= 3x - 4x = 20 - 30
= -x = -10
= x = 10

Present ages of both sisters are x+5 , 2x+5, as this ratio is taken 5years before..

x = 10
Therefore ages of the sisters are
x = 10 years
2x = 20 years

Here's the solution for your problem.......

Answer 2

The answer is given above